Optimal. Leaf size=382 \[ -\frac {(i A+B-i C) (c-i d)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{(a-i b)^{3/2} f}-\frac {(B-i (A-C)) (c+i d)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{(a+i b)^{3/2} f}+\frac {\sqrt {d} (3 b c C+2 b B d-3 a C d) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{b^{5/2} f}+\frac {\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b^2 \left (a^2+b^2\right ) f}-\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b \left (a^2+b^2\right ) f \sqrt {a+b \tan (e+f x)}} \]
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Rubi [A]
time = 4.28, antiderivative size = 382, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 9, integrand size = 49, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.184, Rules used = {3726, 3728,
3736, 6857, 65, 223, 212, 95, 214} \begin {gather*} -\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b f \left (a^2+b^2\right ) \sqrt {a+b \tan (e+f x)}}+\frac {d \left (3 a^2 C-2 a b B+2 A b^2+b^2 C\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b^2 f \left (a^2+b^2\right )}-\frac {(c-i d)^{3/2} (i A+B-i C) \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f (a-i b)^{3/2}}-\frac {(c+i d)^{3/2} (B-i (A-C)) \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f (a+i b)^{3/2}}+\frac {\sqrt {d} (-3 a C d+2 b B d+3 b c C) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{b^{5/2} f} \end {gather*}
Antiderivative was successfully verified.
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Rule 65
Rule 95
Rule 212
Rule 214
Rule 223
Rule 3726
Rule 3728
Rule 3736
Rule 6857
Rubi steps
\begin {align*} \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{(a+b \tan (e+f x))^{3/2}} \, dx &=-\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b \left (a^2+b^2\right ) f \sqrt {a+b \tan (e+f x)}}+\frac {2 \int \frac {\sqrt {c+d \tan (e+f x)} \left (\frac {1}{2} ((b B-a C) (b c-3 a d)+A b (a c+3 b d))-\frac {1}{2} b ((A-C) (b c-a d)-B (a c+b d)) \tan (e+f x)+\frac {1}{2} \left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx}{b \left (a^2+b^2\right )}\\ &=\frac {\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b^2 \left (a^2+b^2\right ) f}-\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b \left (a^2+b^2\right ) f \sqrt {a+b \tan (e+f x)}}+\frac {2 \int \frac {\frac {1}{4} \left (-\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d (b c+a d)+2 b c ((b B-a C) (b c-3 a d)+A b (a c+3 b d))\right )+\frac {1}{2} b^2 \left (2 a A c d-2 a c C d-A b \left (c^2-d^2\right )+a B \left (c^2-d^2\right )+b \left (c^2 C+2 B c d-C d^2\right )\right ) \tan (e+f x)+\frac {1}{4} \left (a^2+b^2\right ) d (3 b c C+2 b B d-3 a C d) \tan ^2(e+f x)}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}} \, dx}{b^2 \left (a^2+b^2\right )}\\ &=\frac {\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b^2 \left (a^2+b^2\right ) f}-\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b \left (a^2+b^2\right ) f \sqrt {a+b \tan (e+f x)}}+\frac {2 \text {Subst}\left (\int \frac {\frac {1}{4} \left (-\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d (b c+a d)+2 b c ((b B-a C) (b c-3 a d)+A b (a c+3 b d))\right )+\frac {1}{2} b^2 \left (2 a A c d-2 a c C d-A b \left (c^2-d^2\right )+a B \left (c^2-d^2\right )+b \left (c^2 C+2 B c d-C d^2\right )\right ) x+\frac {1}{4} \left (a^2+b^2\right ) d (3 b c C+2 b B d-3 a C d) x^2}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{b^2 \left (a^2+b^2\right ) f}\\ &=\frac {\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b^2 \left (a^2+b^2\right ) f}-\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b \left (a^2+b^2\right ) f \sqrt {a+b \tan (e+f x)}}+\frac {2 \text {Subst}\left (\int \left (\frac {\left (a^2+b^2\right ) d (3 b c C+2 b B d-3 a C d)}{4 \sqrt {a+b x} \sqrt {c+d x}}+\frac {-b^2 \left (a \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )-b \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )\right )+b^2 \left (2 a A c d-2 a c C d-A b \left (c^2-d^2\right )+a B \left (c^2-d^2\right )+b \left (c^2 C+2 B c d-C d^2\right )\right ) x}{2 \sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )}\right ) \, dx,x,\tan (e+f x)\right )}{b^2 \left (a^2+b^2\right ) f}\\ &=\frac {\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b^2 \left (a^2+b^2\right ) f}-\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b \left (a^2+b^2\right ) f \sqrt {a+b \tan (e+f x)}}+\frac {\text {Subst}\left (\int \frac {-b^2 \left (a \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )-b \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )\right )+b^2 \left (2 a A c d-2 a c C d-A b \left (c^2-d^2\right )+a B \left (c^2-d^2\right )+b \left (c^2 C+2 B c d-C d^2\right )\right ) x}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{b^2 \left (a^2+b^2\right ) f}+\frac {(d (3 b c C+2 b B d-3 a C d)) \text {Subst}\left (\int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 b^2 f}\\ &=\frac {\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b^2 \left (a^2+b^2\right ) f}-\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b \left (a^2+b^2\right ) f \sqrt {a+b \tan (e+f x)}}+\frac {\text {Subst}\left (\int \left (\frac {-b^2 \left (2 a A c d-2 a c C d-A b \left (c^2-d^2\right )+a B \left (c^2-d^2\right )+b \left (c^2 C+2 B c d-C d^2\right )\right )-i b^2 \left (a \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )-b \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )\right )}{2 (i-x) \sqrt {a+b x} \sqrt {c+d x}}+\frac {b^2 \left (2 a A c d-2 a c C d-A b \left (c^2-d^2\right )+a B \left (c^2-d^2\right )+b \left (c^2 C+2 B c d-C d^2\right )\right )-i b^2 \left (a \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )-b \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )\right )}{2 (i+x) \sqrt {a+b x} \sqrt {c+d x}}\right ) \, dx,x,\tan (e+f x)\right )}{b^2 \left (a^2+b^2\right ) f}+\frac {(d (3 b c C+2 b B d-3 a C d)) \text {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b \tan (e+f x)}\right )}{b^3 f}\\ &=\frac {\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b^2 \left (a^2+b^2\right ) f}-\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b \left (a^2+b^2\right ) f \sqrt {a+b \tan (e+f x)}}+\frac {\left ((i A+B-i C) (c-i d)^2\right ) \text {Subst}\left (\int \frac {1}{(i+x) \sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 (a-i b) f}+\frac {(d (3 b c C+2 b B d-3 a C d)) \text {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{b^3 f}-\frac {\left (b^2 \left (2 a A c d-2 a c C d-A b \left (c^2-d^2\right )+a B \left (c^2-d^2\right )+b \left (c^2 C+2 B c d-C d^2\right )\right )+i b^2 \left (a \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )-b \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )\right )\right ) \text {Subst}\left (\int \frac {1}{(i-x) \sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 b^2 \left (a^2+b^2\right ) f}\\ &=\frac {\sqrt {d} (3 b c C+2 b B d-3 a C d) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{b^{5/2} f}+\frac {\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b^2 \left (a^2+b^2\right ) f}-\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b \left (a^2+b^2\right ) f \sqrt {a+b \tan (e+f x)}}+\frac {\left ((i A+B-i C) (c-i d)^2\right ) \text {Subst}\left (\int \frac {1}{-a+i b-(-c+i d) x^2} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{(a-i b) f}-\frac {\left (b^2 \left (2 a A c d-2 a c C d-A b \left (c^2-d^2\right )+a B \left (c^2-d^2\right )+b \left (c^2 C+2 B c d-C d^2\right )\right )+i b^2 \left (a \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )-b \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )\right )\right ) \text {Subst}\left (\int \frac {1}{a+i b-(c+i d) x^2} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{b^2 \left (a^2+b^2\right ) f}\\ &=-\frac {(i A+B-i C) (c-i d)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{(a-i b)^{3/2} f}+\frac {(i A-B-i C) (c+i d)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{(a+i b)^{3/2} f}+\frac {\sqrt {d} (3 b c C+2 b B d-3 a C d) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{b^{5/2} f}+\frac {\left (2 A b^2-2 a b B+3 a^2 C+b^2 C\right ) d \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b^2 \left (a^2+b^2\right ) f}-\frac {2 \left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{b \left (a^2+b^2\right ) f \sqrt {a+b \tan (e+f x)}}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 4 vs. order 3 in
optimal.
time = 36.19, size = 1073629, normalized size = 2810.55 \begin {gather*} \text {Result too large to show} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 180.00, size = 0, normalized size = 0.00 \[\int \frac {\left (c +d \tan \left (f x +e \right )\right )^{\frac {3}{2}} \left (A +B \tan \left (f x +e \right )+C \left (\tan ^{2}\left (f x +e \right )\right )\right )}{\left (a +b \tan \left (f x +e \right )\right )^{\frac {3}{2}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (c + d \tan {\left (e + f x \right )}\right )^{\frac {3}{2}} \left (A + B \tan {\left (e + f x \right )} + C \tan ^{2}{\left (e + f x \right )}\right )}{\left (a + b \tan {\left (e + f x \right )}\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F(-1)]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \text {Hanged} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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